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252411543403351 = 312994392641369
BaseRepresentation
bin111001011001000100100100…
…011000011011101101010111
31020002201022022110011012011121
4321121010210120123231113
5231041002320102401401
62252500132351144411
7104111063230536133
oct7131044430335527
91202638273135147
10252411543403351
1173476152994392
122438706b215107
13aaac3ca24c927
151e2ac0bc02ca1
hexe5912461bb57

252411543403351 has 12 divisors (see below), whose sum is σ = 260819227970400. Its totient is φ = 244266686601120.

The previous prime is 252411543403309. The next prime is 252411543403391. The reversal of 252411543403351 is 153304345114252.

252411543403351 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 252411543403351 - 215 = 252411543370583 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 252411543403298 and 252411543403307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (252411543403391) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 94240195 + ... + 96881563.

It is an arithmetic number, because the mean of its divisors is an integer number (21734935664200).

Almost surely, 2252411543403351 is an apocalyptic number.

252411543403351 is a deficient number, since it is larger than the sum of its proper divisors (8407684567049).

252411543403351 is an equidigital number, since it uses as much as digits as its factorization.

252411543403351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2740870 (or 2740839 counting only the distinct ones).

The product of its (nonzero) digits is 864000, while the sum is 43.

The spelling of 252411543403351 in words is "two hundred fifty-two trillion, four hundred eleven billion, five hundred forty-three million, four hundred three thousand, three hundred fifty-one".