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25304112035 = 5113349112829
BaseRepresentation
bin10111100100001111…
…100001101110100011
32102022111011002002122
4113210033201232203
5403310323041120
615342522534455
71554026255246
oct274417415643
972274132078
1025304112035
11a805569994
124aa236742b
132503543b77
14132090b25d
159d1744a25
hex5e43e1ba3

25304112035 has 16 divisors (see below), whose sum is σ = 30644814240. Its totient is φ = 20056834560.

The previous prime is 25304112019. The next prime is 25304112037. The reversal of 25304112035 is 53021140352.

It is a happy number.

It is not a de Polignac number, because 25304112035 - 24 = 25304112019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 25304111995 and 25304112013.

It is not an unprimeable number, because it can be changed into a prime (25304112037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1966001 + ... + 1978829.

It is an arithmetic number, because the mean of its divisors is an integer number (1915300890).

Almost surely, 225304112035 is an apocalyptic number.

25304112035 is a deficient number, since it is larger than the sum of its proper divisors (5340702205).

25304112035 is a wasteful number, since it uses less digits than its factorization.

25304112035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16438.

The product of its (nonzero) digits is 3600, while the sum is 26.

Adding to 25304112035 its reverse (53021140352), we get a palindrome (78325252387).

The spelling of 25304112035 in words is "twenty-five billion, three hundred four million, one hundred twelve thousand, thirty-five".

Divisors: 1 5 113 565 3491 12829 17455 64145 394483 1449677 1972415 7248385 44786039 223930195 5060822407 25304112035