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253134101431352 = 23245912867735941
BaseRepresentation
bin111001100011100101100000…
…001100100100010000111000
31020012021101100202120010220002
4321203211200030210100320
5231134322114431300402
62254212111213252132
7104214223003460141
oct7143454014442070
91205241322503802
10253134101431352
117372462a07a329
1224483102494048
13ab3259c03011b
144671a821c8ac8
151e3e8eb3b5602
hexe63960324438

253134101431352 has 16 divisors (see below), whose sum is σ = 474819456259800. Its totient is φ = 126515579762080.

The previous prime is 253134101431333. The next prime is 253134101431363.

It is a happy number.

253134101431352 is nontrivially palindromic in base 10.

It is a super-3 number, since 3×2531341014313523 (a number of 44 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6433848299 + ... + 6433887642.

Almost surely, 2253134101431352 is an apocalyptic number.

It is an amenable number.

253134101431352 is a deficient number, since it is larger than the sum of its proper divisors (221685354828448).

253134101431352 is a wasteful number, since it uses less digits than its factorization.

253134101431352 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12867738406 (or 12867738402 counting only the distinct ones).

The product of its (nonzero) digits is 129600, while the sum is 38.

It can be divided in two parts, 25313410 and 1431352, that added together give a palindrome (26744762).

The spelling of 253134101431352 in words is "two hundred fifty-three trillion, one hundred thirty-four billion, one hundred one million, four hundred thirty-one thousand, three hundred fifty-two".

Divisors: 1 2 4 8 2459 4918 9836 19672 12867735941 25735471882 51470943764 102941887528 31641762678919 63283525357838 126567050715676 253134101431352