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255000131 is a prime number
BaseRepresentation
bin11110011001011…
…11111001000011
3122202211100102022
433030233321003
51010240001011
641145312055
76214315421
oct1714577103
9582740368
10255000131
11120a39411
127149562b
1340aa3569
1425c1c111
15175c08db
hexf32fe43

255000131 has 2 divisors, whose sum is σ = 255000132. Its totient is φ = 255000130.

The previous prime is 255000113. The next prime is 255000139. The reversal of 255000131 is 131000552.

Together with previous prime (255000113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 255000131 - 226 = 187891267 is a prime.

It is a super-2 number, since 2×2550001312 = 130050133620034322, which contains 22 as substring.

It is a Sophie Germain prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (255000139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127500065 + 127500066.

It is an arithmetic number, because the mean of its divisors is an integer number (127500066).

Almost surely, 2255000131 is an apocalyptic number.

255000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

255000131 is an equidigital number, since it uses as much as digits as its factorization.

255000131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 150, while the sum is 17.

The square root of 255000131 is about 15968.7235244399. The cubic root of 255000131 is about 634.1326791285.

Adding to 255000131 its reverse (131000552), we get a palindrome (386000683).

The spelling of 255000131 in words is "two hundred fifty-five million, one hundred thirty-one", and thus it is an aban number.