Base | Representation |
---|---|
bin | 1110110110010001010… |
… | …0110011110011001001 |
3 | 220101102101202222110222 |
4 | 3231210110303303021 |
5 | 13134404034401423 |
6 | 313103543315425 |
7 | 24300163216355 |
oct | 3554424636311 |
9 | 811371688428 |
10 | 255086247113 |
11 | 991aa599a65 |
12 | 4152ba4bb75 |
13 | 1b092a57479 |
14 | c4bc124465 |
15 | 697e60a3c8 |
hex | 3b64533cc9 |
255086247113 has 2 divisors, whose sum is σ = 255086247114. Its totient is φ = 255086247112.
The previous prime is 255086247089. The next prime is 255086247133. The reversal of 255086247113 is 311742680552.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 237117380809 + 17968866304 = 486947^2 + 134048^2 .
It is a cyclic number.
It is not a de Polignac number, because 255086247113 - 212 = 255086243017 is a prime.
It is not a weakly prime, because it can be changed into another prime (255086247133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127543123556 + 127543123557.
It is an arithmetic number, because the mean of its divisors is an integer number (127543123557).
Almost surely, 2255086247113 is an apocalyptic number.
It is an amenable number.
255086247113 is a deficient number, since it is larger than the sum of its proper divisors (1).
255086247113 is an equidigital number, since it uses as much as digits as its factorization.
255086247113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 403200, while the sum is 44.
The spelling of 255086247113 in words is "two hundred fifty-five billion, eighty-six million, two hundred forty-seven thousand, one hundred thirteen".
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