Base | Representation |
---|---|
bin | 1001100001010000… |
… | …1101010001111111 |
3 | 20121002111111120211 |
4 | 2120110031101333 |
5 | 20213142342421 |
6 | 1101323453251 |
7 | 120216555136 |
oct | 23024152177 |
9 | 6532444524 |
10 | 2555434111 |
11 | 10a152651a |
12 | 5b3987227 |
13 | 31956b0b9 |
14 | 1a356091d |
15 | ee52a9e1 |
hex | 9850d47f |
2555434111 has 2 divisors, whose sum is σ = 2555434112. Its totient is φ = 2555434110.
The previous prime is 2555434109. The next prime is 2555434117. The reversal of 2555434111 is 1114345552.
2555434111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2555434111 - 21 = 2555434109 is a prime.
Together with 2555434109, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2555434117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1277717055 + 1277717056.
It is an arithmetic number, because the mean of its divisors is an integer number (1277717056).
Almost surely, 22555434111 is an apocalyptic number.
2555434111 is a deficient number, since it is larger than the sum of its proper divisors (1).
2555434111 is an equidigital number, since it uses as much as digits as its factorization.
2555434111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12000, while the sum is 31.
The square root of 2555434111 is about 50551.3017735449. The cubic root of 2555434111 is about 1367.1669858105.
Adding to 2555434111 its reverse (1114345552), we get a palindrome (3669779663).
The spelling of 2555434111 in words is "two billion, five hundred fifty-five million, four hundred thirty-four thousand, one hundred eleven".
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