Search a number
-
+
25613 = 73659
BaseRepresentation
bin110010000001101
31022010122
412100031
51304423
6314325
7134450
oct62015
938118
1025613
1118275
12129a5
13b873
149497
1578c8
hex640d

25613 has 4 divisors (see below), whose sum is σ = 29280. Its totient is φ = 21948.

The previous prime is 25609. The next prime is 25621. The reversal of 25613 is 31652.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25613 - 22 = 25609 is a prime.

It is a Duffinian number.

It is a nialpdrome in base 13.

It is a junction number, because it is equal to n+sod(n) for n = 25591 and 25600.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25603) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1823 + ... + 1836.

It is an arithmetic number, because the mean of its divisors is an integer number (7320).

225613 is an apocalyptic number.

It is an amenable number.

25613 is a deficient number, since it is larger than the sum of its proper divisors (3667).

25613 is an equidigital number, since it uses as much as digits as its factorization.

25613 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3666.

The product of its digits is 180, while the sum is 17.

The square root of 25613 is about 160.0406198438. The cubic root of 25613 is about 29.4772399376.

The spelling of 25613 in words is "twenty-five thousand, six hundred thirteen".

Divisors: 1 7 3659 25613