Base | Representation |
---|---|

bin | 10111111110010010… |

… | …010101110110011111 |

3 | 2110102221100012111202 |

4 | 113332102111312133 |

5 | 410204202314224 |

6 | 15454132110115 |

7 | 1600613243456 |

oct | 277622256637 |

9 | 73387305452 |

10 | 25741057439 |

11 | aa0a179499 |

12 | 4ba476533b |

13 | 2572c1c846 |

14 | 136296bb9d |

15 | a09ca4eae |

hex | 5fe495d9f |

25741057439 has 2 divisors, whose sum is σ = 25741057440. Its totient is φ = 25741057438.

The previous prime is 25741057411. The next prime is 25741057451. The reversal of 25741057439 is 93475014752.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^{k}-25741057439 is a prime.

It is a junction number, because it is equal to *n*+sod(*n*) for *n* = 25741057393 and 25741057402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25741057339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12870528719 + 12870528720.

It is an arithmetic number, because the mean of its divisors is an integer number (12870528720).

Almost surely, 2^{25741057439} is an apocalyptic number.

25741057439 is a deficient number, since it is larger than the sum of its proper divisors (1).

25741057439 is an equidigital number, since it uses as much as digits as its factorization.

25741057439 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1058400, while the sum is 47.

The spelling of 25741057439 in words is "twenty-five billion, seven hundred forty-one million, fifty-seven thousand, four hundred thirty-nine".

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