Base | Representation |
---|---|
bin | 11001000110001011… |
… | …000101001101001000 |
3 | 2120112222202012210212 |
4 | 121012023011031020 |
5 | 420141430120200 |
6 | 20213534100252 |
7 | 1642526454665 |
oct | 310613051510 |
9 | 76488665725 |
10 | 26947113800 |
11 | 10478a41492 |
12 | 528064a688 |
13 | 2705a54869 |
14 | 1438bd6a6c |
15 | a7aada035 |
hex | 6462c5348 |
26947113800 has 24 divisors (see below), whose sum is σ = 62652040050. Its totient is φ = 10778845440.
The previous prime is 26947113761. The next prime is 26947113857. The reversal of 26947113800 is 831174962.
It can be written as a sum of positive squares in 3 ways, for example, as 12451435396 + 14495678404 = 111586^2 + 120398^2 .
It is a super-2 number, since 2×269471138002 (a number of 22 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 67367585 + ... + 67367984.
Almost surely, 226947113800 is an apocalyptic number.
26947113800 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
26947113800 is an abundant number, since it is smaller than the sum of its proper divisors (35704926250).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
26947113800 is a wasteful number, since it uses less digits than its factorization.
26947113800 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 134735585 (or 134735576 counting only the distinct ones).
The product of its (nonzero) digits is 72576, while the sum is 41.
The spelling of 26947113800 in words is "twenty-six billion, nine hundred forty-seven million, one hundred thirteen thousand, eight hundred".
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