27114433 has 4 divisors (see below), whose sum is σ = 27134548. Its totient is φ = 27094320.

The previous prime is 27114421. The next prime is 27114457. The reversal of 27114433 is 33441172.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 15499969 + 11614464 = 3937^2 + 3408^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-27114433 is a prime.

It is a super-2 number, since 2×27114433² = 1470384953822978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 27114398 and 27114407.

It is not an unprimeable number, because it can be changed into a prime (27114733) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7878 + ... + 10783.

It is an arithmetic number, because the mean of its divisors is an integer number (6783637).

Almost surely, 2^27114433 is an apocalyptic number.

It is an amenable number.

27114433 is a deficient number, since it is larger than the sum of its proper divisors (20115).

27114433 is a wasteful number, since it uses less digits than its factorization.

27114433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20114.

The product of its digits is 2016, while the sum is 25.

The square root of 27114433 is about 5207.1521007169. The cubic root of 27114433 is about 300.4232285704.

The spelling of 27114433 in words is "twenty-seven million, one hundred fourteen thousand, four hundred thirty-three".