Base | Representation |
---|---|
bin | 1110001001001100011001… |
… | …11110010000010001000010 |
3 | 11002010100021102022220001212 |
4 | 13010212030332100101002 |
5 | 13034034323132221010 |
6 | 150052055242130122 |
7 | 6360030042130514 |
oct | 704461476202102 |
9 | 132110242286055 |
10 | 31102223320130 |
11 | 9a0141925a3a6 |
12 | 35a399b7b0942 |
13 | 1447c08a22561 |
14 | 7974d9c41bb4 |
15 | 38e090a51505 |
hex | 1c498cf90442 |
31102223320130 has 16 divisors (see below), whose sum is σ = 56065020804864. Its totient is φ = 12422885143920.
The previous prime is 31102223320061. The next prime is 31102223320141. The reversal of 31102223320130 is 3102332220113.
It is a super-3 number, since 3×311022233201303 (a number of 41 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31102223320096 and 31102223320105.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2250515762 + ... + 2250529581.
It is an arithmetic number, because the mean of its divisors is an integer number (3504063800304).
Almost surely, 231102223320130 is an apocalyptic number.
31102223320130 is a deficient number, since it is larger than the sum of its proper divisors (24962797484734).
31102223320130 is a wasteful number, since it uses less digits than its factorization.
31102223320130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4501046041.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 31102223320130 its reverse (3102332220113), we get a palindrome (34204555540243).
The spelling of 31102223320130 in words is "thirty-one trillion, one hundred two billion, two hundred twenty-three million, three hundred twenty thousand, one hundred thirty".
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