Base | Representation |
---|---|
bin | 1011100110001111… |
… | …1101000010111001 |
3 | 22000222001110022121 |
4 | 2321203331002321 |
5 | 22333440210131 |
6 | 1232530521241 |
7 | 140101564054 |
oct | 27143750271 |
9 | 8028043277 |
10 | 3113210041 |
11 | 1358364867 |
12 | 72a736221 |
13 | 3a7ca1a26 |
14 | 217675a9b |
15 | 1334a7911 |
hex | b98fd0b9 |
3113210041 has 2 divisors, whose sum is σ = 3113210042. Its totient is φ = 3113210040.
The previous prime is 3113210033. The next prime is 3113210069. The reversal of 3113210041 is 1400123113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2500400016 + 612810025 = 50004^2 + 24755^2 .
It is an emirp because it is prime and its reverse (1400123113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3113210041 - 23 = 3113210033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3113209997 and 3113210024.
It is not a weakly prime, because it can be changed into another prime (3113210071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556605020 + 1556605021.
It is an arithmetic number, because the mean of its divisors is an integer number (1556605021).
Almost surely, 23113210041 is an apocalyptic number.
It is an amenable number.
3113210041 is a deficient number, since it is larger than the sum of its proper divisors (1).
3113210041 is an equidigital number, since it uses as much as digits as its factorization.
3113210041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
The square root of 3113210041 is about 55796.1471877763. The cubic root of 3113210041 is about 1460.1679360525.
Adding to 3113210041 its reverse (1400123113), we get a palindrome (4513333154).
The spelling of 3113210041 in words is "three billion, one hundred thirteen million, two hundred ten thousand, forty-one".
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