311430000000000 has 968 divisors, whose sum is σ = 1186620288198016. Its totient is φ = 71136000000000.

The previous prime is 311429999999971. The next prime is 311430000000013. The reversal of 311430000000000 is 34113.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 87 ways as a sum of consecutive naturals, for example, 209999999259 + ... + 210000000741.

Almost surely, 2^{311430000000000} is an apocalyptic number.

311430000000000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 311430000000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (593310144099008).

311430000000000 is an abundant number, since it is smaller than the sum of its proper divisors (875190288198016).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

311430000000000 is an frugal number, since it uses more digits than its factorization.

311430000000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1563 (or 1500 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 12.

Adding to 311430000000000 its reverse (34113), we get a palindrome (311430000034113).

The spelling of 311430000000000 in words is "three hundred eleven trillion, four hundred thirty billion", and thus it is an aban number.