Base | Representation |
---|---|

bin | 1110001100011000111001… |

… | …11101011010001010000000 |

3 | 11002111211122212100122210220 |

4 | 13012030130331122022000 |

5 | 13042334200334400000 |

6 | 150214333444223040 |

7 | 6400664532534033 |

oct | 706143475321200 |

9 | 132454585318726 |

10 | 31212013200000 |

11 | 9a43a38835106 |

12 | 360112009aa80 |

13 | 1455384830a09 |

14 | 79c95316b01a |

15 | 391d694911a0 |

hex | 1c631cf5a280 |

31212013200000 has 192 divisors, whose sum is σ = 103627009009440. Its totient is φ = 8323203200000.

The previous prime is 31212013199993. The next prime is 31212013200013. The reversal of 31212013200000 is 231021213.

Adding to 31212013200000 its reverse (231021213), we get a palindrome (31212244221213).

It is a tau number, because it is divible by the number of its divisors (192).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 11805006 + ... + 14205005.

Almost surely, 2^{31212013200000} is an apocalyptic number.

31212013200000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

31212013200000 is an abundant number, since it is smaller than the sum of its proper divisors (72414995809440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31212013200000 is an frugal number, since it uses more digits than its factorization.

31212013200000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26010053 (or 26010021 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

The spelling of 31212013200000 in words is "thirty-one trillion, two hundred twelve billion, thirteen million, two hundred thousand".

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