Base | Representation |
---|---|
bin | 1110001100011010110011… |
… | …01000110001110100110111 |
3 | 11002111221021210220112011111 |
4 | 13012031121220301310313 |
5 | 13042343241441431403 |
6 | 150215022451415451 |
7 | 6401032003443142 |
oct | 706153150616467 |
9 | 132457253815144 |
10 | 31213031202103 |
11 | 9a44410434163 |
12 | 3601364bb4587 |
13 | 14554b7701b1a |
14 | 79ca0c443059 |
15 | 391dc8a2b56d |
hex | 1c6359a31d37 |
31213031202103 has 4 divisors (see below), whose sum is σ = 31213472652280. Its totient is φ = 31212589751928.
The previous prime is 31213031202061. The next prime is 31213031202149. The reversal of 31213031202103 is 30120213031213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31213031202103 - 233 = 31204441267511 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31213031202203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220619013 + ... + 220760446.
It is an arithmetic number, because the mean of its divisors is an integer number (7803368163070).
Almost surely, 231213031202103 is an apocalyptic number.
31213031202103 is a deficient number, since it is larger than the sum of its proper divisors (441450177).
31213031202103 is an equidigital number, since it uses as much as digits as its factorization.
31213031202103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 441450176.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 31213031202103 its reverse (30120213031213), we get a palindrome (61333244233316).
The spelling of 31213031202103 in words is "thirty-one trillion, two hundred thirteen billion, thirty-one million, two hundred two thousand, one hundred three".
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