Search a number
-
+
312141433102439 is a prime number
BaseRepresentation
bin100011011111001000001011…
…1001111010110000001100111
31111221012102121011100201100212
41012332100113033112001213
5311403111123333234224
63023511443400330035
7122514321461154113
oct10676202717260147
91457172534321325
10312141433102439
1190504490526546
122b01312647391b
1310522a705552a5
145711a240d0743
1526147ad1d3d0e
hex11be4173d6067

312141433102439 has 2 divisors, whose sum is σ = 312141433102440. Its totient is φ = 312141433102438.

The previous prime is 312141433102321. The next prime is 312141433102531. The reversal of 312141433102439 is 934201334141213.

It is a strong prime.

It is an emirp because it is prime and its reverse (934201334141213) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 312141433102439 - 28 = 312141433102183 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 312141433102396 and 312141433102405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (312141433101439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156070716551219 + 156070716551220.

It is an arithmetic number, because the mean of its divisors is an integer number (156070716551220).

Almost surely, 2312141433102439 is an apocalyptic number.

312141433102439 is a deficient number, since it is larger than the sum of its proper divisors (1).

312141433102439 is an equidigital number, since it uses as much as digits as its factorization.

312141433102439 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 186624, while the sum is 41.

The spelling of 312141433102439 in words is "three hundred twelve trillion, one hundred forty-one billion, four hundred thirty-three million, one hundred two thousand, four hundred thirty-nine".