Base | Representation |
---|---|
bin | 100011011111001000001011… |
… | …1001111010110000001100111 |
3 | 1111221012102121011100201100212 |
4 | 1012332100113033112001213 |
5 | 311403111123333234224 |
6 | 3023511443400330035 |
7 | 122514321461154113 |
oct | 10676202717260147 |
9 | 1457172534321325 |
10 | 312141433102439 |
11 | 90504490526546 |
12 | 2b01312647391b |
13 | 10522a705552a5 |
14 | 5711a240d0743 |
15 | 26147ad1d3d0e |
hex | 11be4173d6067 |
312141433102439 has 2 divisors, whose sum is σ = 312141433102440. Its totient is φ = 312141433102438.
The previous prime is 312141433102321. The next prime is 312141433102531. The reversal of 312141433102439 is 934201334141213.
It is a strong prime.
It is an emirp because it is prime and its reverse (934201334141213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 312141433102439 - 28 = 312141433102183 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 312141433102396 and 312141433102405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312141433101439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156070716551219 + 156070716551220.
It is an arithmetic number, because the mean of its divisors is an integer number (156070716551220).
Almost surely, 2312141433102439 is an apocalyptic number.
312141433102439 is a deficient number, since it is larger than the sum of its proper divisors (1).
312141433102439 is an equidigital number, since it uses as much as digits as its factorization.
312141433102439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 186624, while the sum is 41.
The spelling of 312141433102439 in words is "three hundred twelve trillion, one hundred forty-one billion, four hundred thirty-three million, one hundred two thousand, four hundred thirty-nine".
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