Base | Representation |
---|---|
bin | 100011100001000010100000… |
… | …1010000101110100110111000 |
3 | 1111222010112200001000100212101 |
4 | 1013002011001100232212320 |
5 | 311421412130031112100 |
6 | 3024232250534353144 |
7 | 122542311412336024 |
oct | 10702050120564670 |
9 | 1458115601010771 |
10 | 312404131113400 |
11 | 905a5936722327 |
12 | 2b05601b4bb7b4 |
13 | 1054177726c921 |
14 | 57206250db384 |
15 | 261b535b9b86a |
hex | 11c214142e9b8 |
312404131113400 has 48 divisors (see below), whose sum is σ = 726341909747400. Its totient is φ = 124961255902080.
The previous prime is 312404131113367. The next prime is 312404131113407. The reversal of 312404131113400 is 4311131404213.
It is a super-2 number, since 2×3124041311134002 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (312404131113407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 65331306 + ... + 69949894.
Almost surely, 2312404131113400 is an apocalyptic number.
It is an amenable number.
312404131113400 is an abundant number, since it is smaller than the sum of its proper divisors (413937778634000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
312404131113400 is a wasteful number, since it uses less digits than its factorization.
312404131113400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4956808 (or 4956799 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 312404131113400 its reverse (4311131404213), we get a palindrome (316715262517613).
The spelling of 312404131113400 in words is "three hundred twelve trillion, four hundred four billion, one hundred thirty-one million, one hundred thirteen thousand, four hundred".
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