3231400041323 has 4 divisors (see below), whose sum is σ = 3231406021200. Its totient is φ = 3231394061448.

The previous prime is 3231400041283. The next prime is 3231400041349.

3231400041323 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3231400041323 - 2¹⁴ = 3231400024939 is a prime.

It is a super-2 number, since 2×3231400041323² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3231400041292 and 3231400041301.

It is not an unprimeable number, because it can be changed into a prime (3231400041523) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2088848 + ... + 3290301.

It is an arithmetic number, because the mean of its divisors is an integer number (807851505300).

Almost surely, 2^{3231400041323} is an apocalyptic number.

3231400041323 is a deficient number, since it is larger than the sum of its proper divisors (5979877).

3231400041323 is an equidigital number, since it uses as much as digits as its factorization.

3231400041323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5979876.

The product of its (nonzero) digits is 5184, while the sum is 26.

It can be divided in two parts, 32314000 and 41323, that added together give a palindrome (32355323).

The spelling of 3231400041323 in words is "three trillion, two hundred thirty-one billion, four hundred million, forty-one thousand, three hundred twenty-three".