Base | Representation |
---|---|
bin | 1100010010110011… |
… | …1101101000100111 |
3 | 22111222202112010102 |
4 | 3010230331220213 |
5 | 23224312334002 |
6 | 1303245014315 |
7 | 144531365252 |
oct | 30454755047 |
9 | 8458675112 |
10 | 3300121127 |
11 | 1443917936 |
12 | 78125439b |
13 | 4079254c4 |
14 | 23440c099 |
15 | 144ac8a02 |
hex | c4b3da27 |
3300121127 has 2 divisors, whose sum is σ = 3300121128. Its totient is φ = 3300121126.
The previous prime is 3300121117. The next prime is 3300121217. The reversal of 3300121127 is 7211210033.
Together with next prime (3300121217) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3300121127 - 26 = 3300121063 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3300121099 and 3300121108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3300121117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1650060563 + 1650060564.
It is an arithmetic number, because the mean of its divisors is an integer number (1650060564).
Almost surely, 23300121127 is an apocalyptic number.
3300121127 is a deficient number, since it is larger than the sum of its proper divisors (1).
3300121127 is an equidigital number, since it uses as much as digits as its factorization.
3300121127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 20.
The square root of 3300121127 is about 57446.6807309178. The cubic root of 3300121127 is about 1488.8237683421.
The spelling of 3300121127 in words is "three billion, three hundred million, one hundred twenty-one thousand, one hundred twenty-seven".
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