Base | Representation |
---|---|
bin | 1111000001101101001111… |
… | …11000111010100011101001 |
3 | 11022222222100011221212202121 |
4 | 13200312213320322203221 |
5 | 13312343103012414423 |
6 | 154140112030031241 |
7 | 6650231061462520 |
oct | 740664770724351 |
9 | 138888304855677 |
10 | 33044000123113 |
11 | a58a977683541 |
12 | 3858194948521 |
13 | 1559060987155 |
14 | 8234a3bd74b7 |
15 | 3c483c2a145d |
hex | 1e0da7e3a8e9 |
33044000123113 has 8 divisors (see below), whose sum is σ = 38219566408128. Its totient is φ = 27982182547824.
The previous prime is 33044000123107. The next prime is 33044000123117. The reversal of 33044000123113 is 31132100044033.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 33044000123113 - 213 = 33044000114921 is a prime.
It is not an unprimeable number, because it can be changed into a prime (33044000123117) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28437176806 + ... + 28437177967.
It is an arithmetic number, because the mean of its divisors is an integer number (4777445801016).
Almost surely, 233044000123113 is an apocalyptic number.
It is an amenable number.
33044000123113 is a deficient number, since it is larger than the sum of its proper divisors (5175566285015).
33044000123113 is an equidigital number, since it uses as much as digits as its factorization.
33044000123113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56874354863.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 33044000123113 its reverse (31132100044033), we get a palindrome (64176100167146).
The spelling of 33044000123113 in words is "thirty-three trillion, forty-four billion, one hundred twenty-three thousand, one hundred thirteen".
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