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33304040114 = 2132112605617
BaseRepresentation
bin11111000001000100…
…110101001010110010
310011222000102112100012
4133001010311022302
51021201313240424
623144421054522
72256206445602
oct370104651262
9104860375305
1033304040114
11131402982a4
126555557442
1331a9a60317
14187d196c02
15cedc28b0e
hex7c11352b2

33304040114 has 8 divisors (see below), whose sum is σ = 49993880988. Its totient is φ = 16639413120.

The previous prime is 33304040041. The next prime is 33304040117. The reversal of 33304040114 is 41104040333.

It can be written as a sum of positive squares in 2 ways, for example, as 33042150625 + 261889489 = 181775^2 + 16183^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×333040401142 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 33304040114.

It is not an unprimeable number, because it can be changed into a prime (33304040117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6300167 + ... + 6305450.

Almost surely, 233304040114 is an apocalyptic number.

33304040114 is a deficient number, since it is larger than the sum of its proper divisors (16689840874).

33304040114 is a wasteful number, since it uses less digits than its factorization.

33304040114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12606940.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 33304040114 its reverse (41104040333), we get a palindrome (74408080447).

The spelling of 33304040114 in words is "thirty-three billion, three hundred four million, forty thousand, one hundred fourteen".

Divisors: 1 2 1321 2642 12605617 25211234 16652020057 33304040114