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3340121 = 33110091
BaseRepresentation
bin1100101111011101011001
320021200210012
430233131121
51323340441
6155331305
740250651
oct14573531
96250705
103340121
111981534
121150b35
138cc405
1462d361
1545e9eb
hex32f759

3340121 has 4 divisors (see below), whose sum is σ = 3350544. Its totient is φ = 3329700.

The previous prime is 3340097. The next prime is 3340123. The reversal of 3340121 is 1210433.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3340121 is a prime.

It is a super-2 number, since 2×33401212 = 22312816589282, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3340096 and 3340105.

It is not an unprimeable number, because it can be changed into a prime (3340123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4715 + ... + 5376.

It is an arithmetic number, because the mean of its divisors is an integer number (837636).

Almost surely, 23340121 is an apocalyptic number.

It is an amenable number.

3340121 is a deficient number, since it is larger than the sum of its proper divisors (10423).

3340121 is a wasteful number, since it uses less digits than its factorization.

3340121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10422.

The product of its (nonzero) digits is 72, while the sum is 14.

The square root of 3340121 is about 1827.5997920770. The cubic root of 3340121 is about 149.4814837453.

Adding to 3340121 its reverse (1210433), we get a palindrome (4550554).

The spelling of 3340121 in words is "three million, three hundred forty thousand, one hundred twenty-one".

Divisors: 1 331 10091 3340121