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3344424113030 = 25711134110180683
BaseRepresentation
bin110000101010101111001…
…101100001001110000110
3102211201112200000001211212
4300222233031201032012
5414243340033104110
611040223543331422
7463424642625110
oct60525715411606
912751480001755
103344424113030
11107a3a924a680
12460208a50b72
131b34bb167610
14b7c29dda3b0
155bee1ed7e05
hex30aaf361386

3344424113030 has 256 divisors, whose sum is σ = 8361970993152. Its totient is φ = 929456640000.

The previous prime is 3344424112999. The next prime is 3344424113057. The reversal of 3344424113030 is 303114244433.

It is a super-3 number, since 3×33444241130303 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 41411069 + ... + 41491751.

It is an arithmetic number, because the mean of its divisors is an integer number (32663949192).

Almost surely, 23344424113030 is an apocalyptic number.

3344424113030 is an abundant number, since it is smaller than the sum of its proper divisors (5017546880122).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3344424113030 is a wasteful number, since it uses less digits than its factorization.

3344424113030 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 80863.

The product of its (nonzero) digits is 41472, while the sum is 32.

Adding to 3344424113030 its reverse (303114244433), we get a palindrome (3647538357463).

The spelling of 3344424113030 in words is "three trillion, three hundred forty-four billion, four hundred twenty-four million, one hundred thirteen thousand, thirty".