Base | Representation |
---|---|
bin | 110000101010101111001… |
… | …101100001001110000110 |
3 | 102211201112200000001211212 |
4 | 300222233031201032012 |
5 | 414243340033104110 |
6 | 11040223543331422 |
7 | 463424642625110 |
oct | 60525715411606 |
9 | 12751480001755 |
10 | 3344424113030 |
11 | 107a3a924a680 |
12 | 460208a50b72 |
13 | 1b34bb167610 |
14 | b7c29dda3b0 |
15 | 5bee1ed7e05 |
hex | 30aaf361386 |
3344424113030 has 256 divisors, whose sum is σ = 8361970993152. Its totient is φ = 929456640000.
The previous prime is 3344424112999. The next prime is 3344424113057. The reversal of 3344424113030 is 303114244433.
It is a super-3 number, since 3×33444241130303 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 41411069 + ... + 41491751.
It is an arithmetic number, because the mean of its divisors is an integer number (32663949192).
Almost surely, 23344424113030 is an apocalyptic number.
3344424113030 is an abundant number, since it is smaller than the sum of its proper divisors (5017546880122).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3344424113030 is a wasteful number, since it uses less digits than its factorization.
3344424113030 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 80863.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 3344424113030 its reverse (303114244433), we get a palindrome (3647538357463).
The spelling of 3344424113030 in words is "three trillion, three hundred forty-four billion, four hundred twenty-four million, one hundred thirteen thousand, thirty".
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