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3413121101433 = 321989523428809
BaseRepresentation
bin110001101010101101110…
…111101110111001111001
3110002021212021111122211200
4301222231313232321321
5421410033000221213
611131544410244413
7501406215452121
oct61525567567171
913067767448750
103413121101433
1110a655097785a
1247159b426709
131b9b18661294
14bb2a5949c81
155dbb3011273

3413121101433 has 48 divisors (see below), whose sum is σ = 5257896696000. Its totient is φ = 2127354223104.

The previous prime is 3413121101363. The next prime is 3413121101459. The reversal of 3413121101433 is 3341011213143.

Adding to 3413121101433 its reverse (3341011213143), we get a palindrome (6754132314576).

3413121101433 is a `hidden beast` number, since 3 + 4 + 1 + 3 + 121 + 101 + 433 = 666.

It is a de Polignac number, because none of the positive numbers 2k-3413121101433 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 3413121101397 and 3413121101406.

It is not an unprimeable number, because it can be changed into a prime (3413121101333) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 7745133 + ... + 8173941.

It is an arithmetic number, because the mean of its divisors is an integer number (109539514500).

Almost surely, 23413121101433 is an apocalyptic number.

It is an amenable number.

3413121101433 is a deficient number, since it is larger than the sum of its proper divisors (1844775594567).

3413121101433 is a wasteful number, since it uses less digits than its factorization.

3413121101433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 429446 (or 429443 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

The spelling of 3413121101433 in words is "three trillion, four hundred thirteen billion, one hundred twenty-one million, one hundred one thousand, four hundred thirty-three".