Base | Representation |
---|---|
bin | 110001110001001110100… |
… | …001101001101111010001 |
3 | 110002221220110000020110121 |
4 | 301301032201221233101 |
5 | 422013342010142202 |
6 | 11135102201030241 |
7 | 502044356224615 |
oct | 61611641515721 |
9 | 13087813006417 |
10 | 3420111412177 |
11 | 10a9508803779 |
12 | 472a10485381 |
13 | 1ba690953c25 |
14 | bb76a0a3345 |
15 | 5de71a64537 |
hex | 31c4e869bd1 |
3420111412177 has 2 divisors, whose sum is σ = 3420111412178. Its totient is φ = 3420111412176.
The previous prime is 3420111412121. The next prime is 3420111412253. The reversal of 3420111412177 is 7712141110243.
3420111412177 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1795088156481 + 1625023255696 = 1339809^2 + 1274764^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3420111412177 is a prime.
It is not a weakly prime, because it can be changed into another prime (3420111412877) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1710055706088 + 1710055706089.
It is an arithmetic number, because the mean of its divisors is an integer number (1710055706089).
Almost surely, 23420111412177 is an apocalyptic number.
It is an amenable number.
3420111412177 is a deficient number, since it is larger than the sum of its proper divisors (1).
3420111412177 is an equidigital number, since it uses as much as digits as its factorization.
3420111412177 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9408, while the sum is 34.
The spelling of 3420111412177 in words is "three trillion, four hundred twenty billion, one hundred eleven million, four hundred twelve thousand, one hundred seventy-seven".
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