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34314340052381 is a prime number
BaseRepresentation
bin1111100110101011011100…
…00011001010110110011101
311111111102022100122121220112
413303111232003022312131
513444201232023134011
6200551442403255405
710141062222636614
oct763255603126635
9144442270577815
1034314340052381
11aa2a6a2428584
123a2242307a565
13161ba9cc5787c
14868b7414287b
153e78dc34758b
hex1f356e0cad9d

34314340052381 has 2 divisors, whose sum is σ = 34314340052382. Its totient is φ = 34314340052380.

The previous prime is 34314340052353. The next prime is 34314340052417. The reversal of 34314340052381 is 18325004341343.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 24766209152356 + 9548130900025 = 4976566^2 + 3090005^2 .

It is a cyclic number.

It is not a de Polignac number, because 34314340052381 - 210 = 34314340051357 is a prime.

It is a super-2 number, since 2×343143400523812 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34314340052081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17157170026190 + 17157170026191.

It is an arithmetic number, because the mean of its divisors is an integer number (17157170026191).

Almost surely, 234314340052381 is an apocalyptic number.

It is an amenable number.

34314340052381 is a deficient number, since it is larger than the sum of its proper divisors (1).

34314340052381 is an equidigital number, since it uses as much as digits as its factorization.

34314340052381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 414720, while the sum is 41.

The spelling of 34314340052381 in words is "thirty-four trillion, three hundred fourteen billion, three hundred forty million, fifty-two thousand, three hundred eighty-one".