Base | Representation |
---|---|
bin | 100000001000100101… |
… | …111101111100000101 |
3 | 10022001122012012012012 |
4 | 200020211331330011 |
5 | 1031131000043000 |
6 | 23503442304005 |
7 | 2331016250150 |
oct | 401045757405 |
9 | 108048165165 |
10 | 34503909125 |
11 | 136a6614684 |
12 | 682b358005 |
13 | 333b509c9a |
14 | 1954690c97 |
15 | d6e23a735 |
hex | 80897df05 |
34503909125 has 48 divisors (see below), whose sum is σ = 49683029760. Its totient is φ = 23435697600.
The previous prime is 34503909049. The next prime is 34503909131. The reversal of 34503909125 is 52190930543.
It is a de Polignac number, because none of the positive numbers 2k-34503909125 is a prime.
It is a super-3 number, since 3×345039091253 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 10394216 + ... + 10397534.
It is an arithmetic number, because the mean of its divisors is an integer number (1035063120).
Almost surely, 234503909125 is an apocalyptic number.
34503909125 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
It is an amenable number.
34503909125 is a deficient number, since it is larger than the sum of its proper divisors (15179120635).
34503909125 is an equidigital number, since it uses as much as digits as its factorization.
34503909125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3559 (or 3440 counting only the distinct ones).
The product of its (nonzero) digits is 145800, while the sum is 41.
The spelling of 34503909125 in words is "thirty-four billion, five hundred three million, nine hundred nine thousand, one hundred twenty-five".
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