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34966743193 is a prime number
BaseRepresentation
bin100000100100001011…
…100010100010011001
310100020220002121011201
4200210023202202121
51033102441240233
624021414354201
72345336261464
oct404413424231
9110226077151
1034966743193
11139138a6778
12693a35b961
1333b337b4b5
141999d302db
15d99bb177d
hex8242e2899

34966743193 has 2 divisors, whose sum is σ = 34966743194. Its totient is φ = 34966743192.

The previous prime is 34966743191. The next prime is 34966743247. The reversal of 34966743193 is 39134766943.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22312293129 + 12654450064 = 149373^2 + 112492^2 .

It is an emirp because it is prime and its reverse (39134766943) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34966743193 - 21 = 34966743191 is a prime.

Together with 34966743191, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (34966743191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17483371596 + 17483371597.

It is an arithmetic number, because the mean of its divisors is an integer number (17483371597).

Almost surely, 234966743193 is an apocalyptic number.

It is an amenable number.

34966743193 is a deficient number, since it is larger than the sum of its proper divisors (1).

34966743193 is an equidigital number, since it uses as much as digits as its factorization.

34966743193 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 8817984, while the sum is 55.

The spelling of 34966743193 in words is "thirty-four billion, nine hundred sixty-six million, seven hundred forty-three thousand, one hundred ninety-three".