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349746240000 = 293541392621
BaseRepresentation
bin1010001011011101000…
…00000001101000000000
31020102202102020212002110
411011232200001220000
521212240014140000
6424400551415320
734161015663123
oct5055640015000
91212672225073
10349746240000
111253656a8743
1257949384540
1326c9a140691
1412cdbc983ba
15916eb2a850
hex516e801a00

349746240000 has 400 divisors, whose sum is σ = 1173133352160. Its totient is φ = 92559360000.

The previous prime is 349746239939. The next prime is 349746240001. The reversal of 349746240000 is 42647943.

It is a tau number, because it is divible by the number of its divisors (400).

It is not an unprimeable number, because it can be changed into a prime (349746240001) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 133438690 + ... + 133441310.

Almost surely, 2349746240000 is an apocalyptic number.

349746240000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 349746240000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (586566676080).

349746240000 is an abundant number, since it is smaller than the sum of its proper divisors (823387112160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

349746240000 is an equidigital number, since it uses as much as digits as its factorization.

349746240000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2801 (or 2770 counting only the distinct ones).

The product of its (nonzero) digits is 145152, while the sum is 39.

Adding to 349746240000 its reverse (42647943), we get a palindrome (349788887943).

The spelling of 349746240000 in words is "three hundred forty-nine billion, seven hundred forty-six million, two hundred forty thousand".