3540998053 has 2 divisors, whose sum is σ = 3540998054. Its totient is φ = 3540998052.

The previous prime is 3540998047. The next prime is 3540998057. The reversal of 3540998053 is 3508990453.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3540012004 + 986049 = 59498^2 + 993^2 .

It is a cyclic number.

It is not a de Polignac number, because 3540998053 - 2¹³ = 3540989861 is a prime.

It is a super-2 number, since 2×3540998053² = 25077334422699581618, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3540997994 and 3540998012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3540998057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1770499026 + 1770499027.

It is an arithmetic number, because the mean of its divisors is an integer number (1770499027).

Almost surely, 2^3540998053 is an apocalyptic number.

It is an amenable number.

3540998053 is a deficient number, since it is larger than the sum of its proper divisors (1).

3540998053 is an equidigital number, since it uses as much as digits as its factorization.

3540998053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 583200, while the sum is 46.

The square root of 3540998053 is about 59506.2858276334. The cubic root of 3540998053 is about 1524.1997848517.

The spelling of 3540998053 in words is "three billion, five hundred forty million, nine hundred ninety-eight thousand, fifty-three".