Base | Representation |
---|---|
bin | 100101010011010110… |
… | …100010000010000001 |
3 | 10211101101000101000121 |
4 | 211103112202002001 |
5 | 1124012044334103 |
6 | 30222233220241 |
7 | 2615360624653 |
oct | 452326420201 |
9 | 124341011017 |
10 | 40053121153 |
11 | 15a93a40821 |
12 | 7919861681 |
13 | 3a140914b6 |
14 | 1d1d6786d3 |
15 | 10964cb6bd |
hex | 9535a2081 |
40053121153 has 4 divisors (see below), whose sum is σ = 40136739840. Its totient is φ = 39969502468.
The previous prime is 40053121091. The next prime is 40053121217. The reversal of 40053121153 is 35112135004.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 40053121153 - 221 = 40051024001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (40053121453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41808625 + ... + 41809582.
It is an arithmetic number, because the mean of its divisors is an integer number (10034184960).
Almost surely, 240053121153 is an apocalyptic number.
It is an amenable number.
40053121153 is a deficient number, since it is larger than the sum of its proper divisors (83618687).
40053121153 is an equidigital number, since it uses as much as digits as its factorization.
40053121153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 83618686.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 40053121153 its reverse (35112135004), we get a palindrome (75165256157).
The spelling of 40053121153 in words is "forty billion, fifty-three million, one hundred twenty-one thousand, one hundred fifty-three".
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