Base | Representation |
---|---|
bin | 111010010110111001010… |
… | …111011011100001111001 |
3 | 112012101022201002020020221 |
4 | 322112321113123201321 |
5 | 1011201110442223301 |
6 | 12310151335420041 |
7 | 562510221040414 |
oct | 72267127334171 |
9 | 15171281066227 |
10 | 4010314414201 |
11 | 1306845a35727 |
12 | 549286224621 |
13 | 23122b98c7c4 |
14 | dc159148b7b |
15 | 6e4b6772da1 |
hex | 3a5b95db879 |
4010314414201 has 2 divisors, whose sum is σ = 4010314414202. Its totient is φ = 4010314414200.
The previous prime is 4010314414031. The next prime is 4010314414213. The reversal of 4010314414201 is 1024144130104.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3168581562601 + 841732851600 = 1780051^2 + 917460^2 .
It is a cyclic number.
It is not a de Polignac number, because 4010314414201 - 215 = 4010314381433 is a prime.
It is not a weakly prime, because it can be changed into another prime (4010314414291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2005157207100 + 2005157207101.
It is an arithmetic number, because the mean of its divisors is an integer number (2005157207101).
Almost surely, 24010314414201 is an apocalyptic number.
It is an amenable number.
4010314414201 is a deficient number, since it is larger than the sum of its proper divisors (1).
4010314414201 is an equidigital number, since it uses as much as digits as its factorization.
4010314414201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 4010314414201 its reverse (1024144130104), we get a palindrome (5034458544305).
The spelling of 4010314414201 in words is "four trillion, ten billion, three hundred fourteen million, four hundred fourteen thousand, two hundred one".
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