401150115131 has 4 divisors (see below), whose sum is σ = 401153544600. Its totient is φ = 401146685664.

The previous prime is 401150115127. The next prime is 401150115133. The reversal of 401150115131 is 131511051104.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 401150115131 - 2² = 401150115127 is a prime.

It is a super-2 number, since 2×401150115131² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 401150115097 and 401150115106.

It is not an unprimeable number, because it can be changed into a prime (401150115133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1532846 + ... + 1775363.

It is an arithmetic number, because the mean of its divisors is an integer number (100288386150).

Almost surely, 2^401150115131 is an apocalyptic number.

401150115131 is a deficient number, since it is larger than the sum of its proper divisors (3429469).

401150115131 is a wasteful number, since it uses less digits than its factorization.

401150115131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3429468.

The product of its (nonzero) digits is 300, while the sum is 23.

Adding to 401150115131 its reverse (131511051104), we get a palindrome (532661166235).

The spelling of 401150115131 in words is "four hundred one billion, one hundred fifty million, one hundred fifteen thousand, one hundred thirty-one".