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4012013 is a prime number
BaseRepresentation
bin1111010011011111101101
321112211110002
433103133231
52011341023
6221554045
746046555
oct17233755
97484402
104012013
1122a0315
121415925
13aa6195
14766165
15543b28
hex3d37ed

4012013 has 2 divisors, whose sum is σ = 4012014. Its totient is φ = 4012012.

The previous prime is 4011991. The next prime is 4012033. The reversal of 4012013 is 3102104.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4012009 + 4 = 2003^2 + 2^2 .

It is a cyclic number.

It is not a de Polignac number, because 4012013 - 216 = 3946477 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4011985 and 4012003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4012033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006006 + 2006007.

It is an arithmetic number, because the mean of its divisors is an integer number (2006007).

Almost surely, 24012013 is an apocalyptic number.

It is an amenable number.

4012013 is a deficient number, since it is larger than the sum of its proper divisors (1).

4012013 is an equidigital number, since it uses as much as digits as its factorization.

4012013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 11.

The square root of 4012013 is about 2003.0009985020. Note that the first 3 decimals coincide. The cubic root of 4012013 is about 158.8988584511.

Adding to 4012013 its reverse (3102104), we get a palindrome (7114117).

Subtracting from 4012013 its reverse (3102104), we obtain a palindrome (909909).

The spelling of 4012013 in words is "four million, twelve thousand, thirteen".