Base | Representation |
---|---|
bin | 100101010111111011… |
… | …111101001001010001 |
3 | 10211120201202021101122 |
4 | 211113323331021101 |
5 | 1124141242243101 |
6 | 30234022012025 |
7 | 2620313500223 |
oct | 452773751121 |
9 | 124521667348 |
10 | 40130040401 |
11 | 160233a8350 |
12 | 793b577015 |
13 | 3a26cb3549 |
14 | 1d2997c413 |
15 | 109d12251b |
hex | 957efd251 |
40130040401 has 4 divisors (see below), whose sum is σ = 43778225904. Its totient is φ = 36481854900.
The previous prime is 40130040367. The next prime is 40130040403. The reversal of 40130040401 is 10404003104.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 40130040401 - 218 = 40129778257 is a prime.
It is a super-2 number, since 2×401300404012 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 40130040401.
It is not an unprimeable number, because it can be changed into a prime (40130040403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1824092735 + ... + 1824092756.
It is an arithmetic number, because the mean of its divisors is an integer number (10944556476).
Almost surely, 240130040401 is an apocalyptic number.
It is an amenable number.
40130040401 is a deficient number, since it is larger than the sum of its proper divisors (3648185503).
40130040401 is a wasteful number, since it uses less digits than its factorization.
40130040401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3648185502.
The product of its (nonzero) digits is 192, while the sum is 17.
Adding to 40130040401 its reverse (10404003104), we get a palindrome (50534043505).
The spelling of 40130040401 in words is "forty billion, one hundred thirty million, forty thousand, four hundred one".
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