Base | Representation |
---|---|
bin | 111010100001110010000… |
… | …000001001101011111001 |
3 | 112020111111020101200220021 |
4 | 322201302000021223321 |
5 | 1011344030010000403 |
6 | 12315403205530441 |
7 | 563402650122115 |
oct | 72416200115371 |
9 | 15214436350807 |
10 | 4022002031353 |
11 | 13107a3325459 |
12 | 54b5a8413a21 |
13 | 2323721ac1b7 |
14 | dc94748c745 |
15 | 6e94c88a8bd |
hex | 3a872009af9 |
4022002031353 has 2 divisors, whose sum is σ = 4022002031354. Its totient is φ = 4022002031352.
The previous prime is 4022002031321. The next prime is 4022002031381. The reversal of 4022002031353 is 3531302002204.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2475043193529 + 1546958837824 = 1573227^2 + 1243768^2 .
It is a cyclic number.
It is not a de Polignac number, because 4022002031353 - 25 = 4022002031321 is a prime.
It is not a weakly prime, because it can be changed into another prime (4022002031153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011001015676 + 2011001015677.
It is an arithmetic number, because the mean of its divisors is an integer number (2011001015677).
Almost surely, 24022002031353 is an apocalyptic number.
It is an amenable number.
4022002031353 is a deficient number, since it is larger than the sum of its proper divisors (1).
4022002031353 is an equidigital number, since it uses as much as digits as its factorization.
4022002031353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 25.
Adding to 4022002031353 its reverse (3531302002204), we get a palindrome (7553304033557).
The spelling of 4022002031353 in words is "four trillion, twenty-two billion, two million, thirty-one thousand, three hundred fifty-three".
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