Base | Representation |
---|---|
bin | 111010110100101110001… |
… | …111110110100010010011 |
3 | 112022102222122010022102122 |
4 | 322310232033312202103 |
5 | 1012212203033224021 |
6 | 12333005254004455 |
7 | 565022646126125 |
oct | 72645617664223 |
9 | 15272878108378 |
10 | 4042340133011 |
11 | 131938a692234 |
12 | 55352364672b |
13 | 23426393538b |
14 | dd916625215 |
15 | 7023d13ebab |
hex | 3ad2e3f6893 |
4042340133011 has 2 divisors, whose sum is σ = 4042340133012. Its totient is φ = 4042340133010.
The previous prime is 4042340132993. The next prime is 4042340133023. The reversal of 4042340133011 is 1103310432404.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4042340133011 - 26 = 4042340132947 is a prime.
It is a super-3 number, since 3×40423401330113 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (4042340133061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021170066505 + 2021170066506.
It is an arithmetic number, because the mean of its divisors is an integer number (2021170066506).
Almost surely, 24042340133011 is an apocalyptic number.
4042340133011 is a deficient number, since it is larger than the sum of its proper divisors (1).
4042340133011 is an equidigital number, since it uses as much as digits as its factorization.
4042340133011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 26.
Adding to 4042340133011 its reverse (1103310432404), we get a palindrome (5145650565415).
The spelling of 4042340133011 in words is "four trillion, forty-two billion, three hundred forty million, one hundred thirty-three thousand, eleven".
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