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40501568212513 is a prime number
BaseRepresentation
bin10010011010110000000011…
…00101100000111000100001
312022101220121221000011200221
421031120001211200320201
520302034202430300023
6222050055155443041
711350066421361262
oct1115300145407041
9168356557004627
1040501568212513
11119a5689422871
1246615852b6481
13197a38759b825
14a00401aba969
154a381337085d
hex24d601960e21

40501568212513 has 2 divisors, whose sum is σ = 40501568212514. Its totient is φ = 40501568212512.

The previous prime is 40501568212489. The next prime is 40501568212561. The reversal of 40501568212513 is 31521286510504.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 24376259821824 + 16125308390689 = 4937232^2 + 4015633^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40501568212513 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 40501568212513.

It is not a weakly prime, because it can be changed into another prime (40501568212583) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20250784106256 + 20250784106257.

It is an arithmetic number, because the mean of its divisors is an integer number (20250784106257).

Almost surely, 240501568212513 is an apocalyptic number.

It is an amenable number.

40501568212513 is a deficient number, since it is larger than the sum of its proper divisors (1).

40501568212513 is an equidigital number, since it uses as much as digits as its factorization.

40501568212513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288000, while the sum is 43.

The spelling of 40501568212513 in words is "forty trillion, five hundred one billion, five hundred sixty-eight million, two hundred twelve thousand, five hundred thirteen".