411025127 has 2 divisors, whose sum is σ = 411025128. Its totient is φ = 411025126.

The previous prime is 411025073. The next prime is 411025159. The reversal of 411025127 is 721520114.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 411025127 - 2¹⁴ = 411008743 is a prime.

It is a super-2 number, since 2×411025127² = 337883310050732258, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (411025427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205512563 + 205512564.

It is an arithmetic number, because the mean of its divisors is an integer number (205512564).

Almost surely, 2^411025127 is an apocalyptic number.

411025127 is a deficient number, since it is larger than the sum of its proper divisors (1).

411025127 is an equidigital number, since it uses as much as digits as its factorization.

411025127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 560, while the sum is 23.

The square root of 411025127 is about 20273.7546349955. The cubic root of 411025127 is about 743.5145254415.

The spelling of 411025127 in words is "four hundred eleven million, twenty-five thousand, one hundred twenty-seven".