Base | Representation |
---|---|
bin | 111011110110110110011… |
… | …011101110011000001101 |
3 | 112120020021001012222202221 |
4 | 323312312123232120031 |
5 | 1014343112133022222 |
6 | 12425351102215341 |
7 | 603115336466164 |
oct | 73666633563015 |
9 | 15506231188687 |
10 | 4113344423437 |
11 | 1346506768597 |
12 | 56523a884551 |
13 | 23ab6b15ca02 |
14 | 1031307843db |
15 | 71ee69cd0c7 |
hex | 3bdb66ee60d |
4113344423437 has 2 divisors, whose sum is σ = 4113344423438. Its totient is φ = 4113344423436.
The previous prime is 4113344423329. The next prime is 4113344423449. The reversal of 4113344423437 is 7343244433114.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4032762814276 + 80581609161 = 2008174^2 + 283869^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4113344423437 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4113344423393 and 4113344423402.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4113344424437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056672211718 + 2056672211719.
It is an arithmetic number, because the mean of its divisors is an integer number (2056672211719).
Almost surely, 24113344423437 is an apocalyptic number.
It is an amenable number.
4113344423437 is a deficient number, since it is larger than the sum of its proper divisors (1).
4113344423437 is an equidigital number, since it uses as much as digits as its factorization.
4113344423437 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1161216, while the sum is 43.
The spelling of 4113344423437 in words is "four trillion, one hundred thirteen billion, three hundred forty-four million, four hundred twenty-three thousand, four hundred thirty-seven".
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