Base | Representation |
---|---|
bin | 111100000000111101100… |
… | …011111001000101111111 |
3 | 112121021021200120201121102 |
4 | 330000331203321011333 |
5 | 1020032331031020411 |
6 | 12434344301323315 |
7 | 603651361454621 |
oct | 74007543710577 |
9 | 15537250521542 |
10 | 4124201423231 |
11 | 135007820519a |
12 | 56736a86653b |
13 | 23bbab569546 |
14 | 10388066cc11 |
15 | 7242ec21d3b |
hex | 3c03d8f917f |
4124201423231 has 2 divisors, whose sum is σ = 4124201423232. Its totient is φ = 4124201423230.
The previous prime is 4124201423227. The next prime is 4124201423239. The reversal of 4124201423231 is 1323241024214.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4124201423231 - 22 = 4124201423227 is a prime.
It is a super-2 number, since 2×41242014232312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4124201423194 and 4124201423203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4124201423239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2062100711615 + 2062100711616.
It is an arithmetic number, because the mean of its divisors is an integer number (2062100711616).
Almost surely, 24124201423231 is an apocalyptic number.
4124201423231 is a deficient number, since it is larger than the sum of its proper divisors (1).
4124201423231 is an equidigital number, since it uses as much as digits as its factorization.
4124201423231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 4124201423231 its reverse (1323241024214), we get a palindrome (5447442447445).
The spelling of 4124201423231 in words is "four trillion, one hundred twenty-four billion, two hundred one million, four hundred twenty-three thousand, two hundred thirty-one".
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