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4233130013401 is a prime number
BaseRepresentation
bin111101100110011010001…
…101011111001011011001
3112222200110002221102222221
4331212122031133023121
51023323422240412101
613000401215144041
7614555623266352
oct75463215371331
915880402842887
104233130013401
111392295598233
125844aa815021
1324924aab5b23
14108c55436d29
15751a7c2eaa1
hex3d99a35f2d9

4233130013401 has 2 divisors, whose sum is σ = 4233130013402. Its totient is φ = 4233130013400.

The previous prime is 4233130013389. The next prime is 4233130013407. The reversal of 4233130013401 is 1043100313324.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4115120587776 + 118009425625 = 2028576^2 + 343525^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4233130013401 is a prime.

It is not a weakly prime, because it can be changed into another prime (4233130013407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2116565006700 + 2116565006701.

It is an arithmetic number, because the mean of its divisors is an integer number (2116565006701).

Almost surely, 24233130013401 is an apocalyptic number.

It is an amenable number.

4233130013401 is a deficient number, since it is larger than the sum of its proper divisors (1).

4233130013401 is an equidigital number, since it uses as much as digits as its factorization.

4233130013401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 4233130013401 its reverse (1043100313324), we get a palindrome (5276230326725).

The spelling of 4233130013401 in words is "four trillion, two hundred thirty-three billion, one hundred thirty million, thirteen thousand, four hundred one".