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4311221979349 is a prime number
BaseRepresentation
bin111110101111001000110…
…110101100100011010101
3120021011000110202100100001
4332233020312230203111
51031113340311314344
613100314213051301
7623322046120435
oct76571066544325
916234013670301
104311221979349
11141241946106a
12597663626b31
132537148332bc
1410c942a162c5
1577228954ed4
hex3ebc8dac8d5

4311221979349 has 2 divisors, whose sum is σ = 4311221979350. Its totient is φ = 4311221979348.

The previous prime is 4311221979331. The next prime is 4311221979439. The reversal of 4311221979349 is 9439791221134.

Together with next prime (4311221979439) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3988080892324 + 323141087025 = 1997018^2 + 568455^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4311221979349 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4311221979349.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4311221976349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2155610989674 + 2155610989675.

It is an arithmetic number, because the mean of its divisors is an integer number (2155610989675).

Almost surely, 24311221979349 is an apocalyptic number.

It is an amenable number.

4311221979349 is a deficient number, since it is larger than the sum of its proper divisors (1).

4311221979349 is an equidigital number, since it uses as much as digits as its factorization.

4311221979349 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2939328, while the sum is 55.

The spelling of 4311221979349 in words is "four trillion, three hundred eleven billion, two hundred twenty-one million, nine hundred seventy-nine thousand, three hundred forty-nine".