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4324231230041 is a prime number
BaseRepresentation
bin111110111011010000010…
…001000011001001011001
3120022101121002221202100202
4332323100101003021121
51031322011143330131
613110305134311545
7624262323664142
oct76732021031131
916271532852322
104324231230041
111417994884718
1259a0943585b5
13254a08ac3788
1410d4186acac9
157773aad2bcb
hex3eed0443259

4324231230041 has 2 divisors, whose sum is σ = 4324231230042. Its totient is φ = 4324231230040.

The previous prime is 4324231230037. The next prime is 4324231230043. The reversal of 4324231230041 is 1400321324234.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2709562905625 + 1614668324416 = 1646075^2 + 1270696^2 .

It is a cyclic number.

It is not a de Polignac number, because 4324231230041 - 22 = 4324231230037 is a prime.

Together with 4324231230043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 4324231229986 and 4324231230013.

It is not a weakly prime, because it can be changed into another prime (4324231230043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2162115615020 + 2162115615021.

It is an arithmetic number, because the mean of its divisors is an integer number (2162115615021).

Almost surely, 24324231230041 is an apocalyptic number.

It is an amenable number.

4324231230041 is a deficient number, since it is larger than the sum of its proper divisors (1).

4324231230041 is an equidigital number, since it uses as much as digits as its factorization.

4324231230041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 4324231230041 its reverse (1400321324234), we get a palindrome (5724552554275).

The spelling of 4324231230041 in words is "four trillion, three hundred twenty-four billion, two hundred thirty-one million, two hundred thirty thousand, forty-one".