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443311113344 = 27111013538831
BaseRepresentation
bin1100111001101110110…
…01101100010010000000
31120101021010001220002212
412130313121230102000
524230400121111334
6535353155401252
744012443201331
oct6346731542200
91511233056085
10443311113344
11161009625950
1271abbbb3228
1332a5b694468
1417656400288
15b7e8e2aece
hex673766c480

443311113344 has 128 divisors (see below), whose sum is σ = 975851919360. Its totient is φ = 198922240000.

The previous prime is 443311113281. The next prime is 443311113367.

443311113344 is nontrivially palindromic in base 10.

It is a tau number, because it is divible by the number of its divisors (128).

It is a Harshad number since it is a multiple of its sum of digits (32).

It is a zygodrome in base 10.

It is a self number, because there is not a number n which added to its sum of digits gives 443311113344.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 50195009 + ... + 50203839.

It is an arithmetic number, because the mean of its divisors is an integer number (7623843120).

Almost surely, 2443311113344 is an apocalyptic number.

443311113344 is a gapful number since it is divisible by the number (44) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 443311113344, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (487925959680).

443311113344 is an abundant number, since it is smaller than the sum of its proper divisors (532540806016).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

443311113344 is a wasteful number, since it uses less digits than its factorization.

443311113344 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9310 (or 9298 counting only the distinct ones).

The product of its digits is 20736, while the sum is 32.

It can be divided in two parts, 443311 and 113344, that added together give a palindrome (556655).

The spelling of 443311113344 in words is "four hundred forty-three billion, three hundred eleven million, one hundred thirteen thousand, three hundred forty-four".

Divisors: 1 2 4 8 11 16 22 32 44 64 88 101 128 176 202 352 353 404 704 706 808 1111 1408 1412 1616 2222 2824 3232 3883 4444 5648 6464 7766 8831 8888 11296 12928 15532 17662 17776 22592 31064 35324 35552 35653 45184 62128 70648 71104 71306 97141 124256 141296 142208 142612 194282 248512 282592 285224 388564 392183 497024 565184 570448 777128 784366 891931 1130368 1140896 1554256 1568732 1783862 2281792 3108512 3117343 3137464 3567724 4563584 6217024 6234686 6274928 7135448 9811241 12434048 12469372 12549856 14270896 19622482 24938744 25099712 28541792 34290773 39244964 49877488 50199424 57083584 68581546 78489928 99754976 114167168 137163092 156979856 199509952 274326184 313959712 314851643 399019904 548652368 627919424 629703286 1097304736 1255838848 1259406572 2194609472 2518813144 3463368073 4389218944 5037626288 6926736146 10075252576 13853472292 20150505152 27706944584 40301010304 55413889168 110827778336 221655556672 443311113344