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46345033326521 is a prime number
BaseRepresentation
bin10101000100110100010110…
…01111111001111110111001
320002002112122001112121102002
422202122023033321332321
522033304112012422041
6242322340412550345
712522214062330446
oct1242321317717671
9202075561477362
1046345033326521
1113848900111546
125245b89a823b5
131cb2419535417
14b6317c2729cd
15555819b8659b
hex2a268b3f9fb9

46345033326521 has 2 divisors, whose sum is σ = 46345033326522. Its totient is φ = 46345033326520.

The previous prime is 46345033326509. The next prime is 46345033326523. The reversal of 46345033326521 is 12562333054364.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 43790790086521 + 2554243240000 = 6617461^2 + 1598200^2 .

It is a cyclic number.

It is not a de Polignac number, because 46345033326521 - 242 = 41946986815417 is a prime.

It is a super-2 number, since 2×463450333265212 (a number of 28 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 46345033326523, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (46345033326523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23172516663260 + 23172516663261.

It is an arithmetic number, because the mean of its divisors is an integer number (23172516663261).

Almost surely, 246345033326521 is an apocalyptic number.

It is an amenable number.

46345033326521 is a deficient number, since it is larger than the sum of its proper divisors (1).

46345033326521 is an equidigital number, since it uses as much as digits as its factorization.

46345033326521 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4665600, while the sum is 47.

The spelling of 46345033326521 in words is "forty-six trillion, three hundred forty-five billion, thirty-three million, three hundred twenty-six thousand, five hundred twenty-one".