Base | Representation |
---|---|
bin | 101101000010100111… |
… | …110101000001111111 |
3 | 11121211110100022122212 |
4 | 231002213311001333 |
5 | 1243021232033333 |
6 | 34114541331035 |
7 | 3331315265450 |
oct | 550247650177 |
9 | 147743308585 |
10 | 48362377343 |
11 | 195683349a5 |
12 | 9458566a7b |
13 | 47396c3537 |
14 | 24ab045127 |
15 | 13d0c13448 |
hex | b429f507f |
48362377343 has 8 divisors (see below), whose sum is σ = 55693207680. Its totient is φ = 41137026840.
The previous prime is 48362377333. The next prime is 48362377361. The reversal of 48362377343 is 34377326384.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 48362377343 - 210 = 48362376319 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 48362377291 and 48362377300.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (48362377333) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26368973 + ... + 26370806.
It is an arithmetic number, because the mean of its divisors is an integer number (6961650960).
Almost surely, 248362377343 is an apocalyptic number.
48362377343 is a deficient number, since it is larger than the sum of its proper divisors (7330830337).
48362377343 is a wasteful number, since it uses less digits than its factorization.
48362377343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52739917.
The product of its digits is 6096384, while the sum is 50.
The spelling of 48362377343 in words is "forty-eight billion, three hundred sixty-two million, three hundred seventy-seven thousand, three hundred forty-three".
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