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484113148211443 is a prime number
BaseRepresentation
bin110111000010011000110000…
…0001110101111000011110011
32100111002202122200010112021211
41232010301200032233003303
51001423202211420231233
64433342302100300551
7203654010054022432
oct15604614016570363
92314082580115254
10484113148211443
111302872623a8353
12463684559a1757
1317a1889b9b08aa
1487792b68a9119
153ae7d621d85cd
hex1b84c603af0f3

484113148211443 has 2 divisors, whose sum is σ = 484113148211444. Its totient is φ = 484113148211442.

The previous prime is 484113148211411. The next prime is 484113148211513. The reversal of 484113148211443 is 344112841311484.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 484113148211443 - 25 = 484113148211411 is a prime.

It is a super-2 number, since 2×4841131482114432 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (484113148211743) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 242056574105721 + 242056574105722.

It is an arithmetic number, because the mean of its divisors is an integer number (242056574105722).

Almost surely, 2484113148211443 is an apocalyptic number.

484113148211443 is a deficient number, since it is larger than the sum of its proper divisors (1).

484113148211443 is an equidigital number, since it uses as much as digits as its factorization.

484113148211443 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1179648, while the sum is 49.

The spelling of 484113148211443 in words is "four hundred eighty-four trillion, one hundred thirteen billion, one hundred forty-eight million, two hundred eleven thousand, four hundred forty-three".