Base | Representation |
---|---|
bin | 110111000010011000110000… |
… | …0001110101111000011110011 |
3 | 2100111002202122200010112021211 |
4 | 1232010301200032233003303 |
5 | 1001423202211420231233 |
6 | 4433342302100300551 |
7 | 203654010054022432 |
oct | 15604614016570363 |
9 | 2314082580115254 |
10 | 484113148211443 |
11 | 1302872623a8353 |
12 | 463684559a1757 |
13 | 17a1889b9b08aa |
14 | 87792b68a9119 |
15 | 3ae7d621d85cd |
hex | 1b84c603af0f3 |
484113148211443 has 2 divisors, whose sum is σ = 484113148211444. Its totient is φ = 484113148211442.
The previous prime is 484113148211411. The next prime is 484113148211513. The reversal of 484113148211443 is 344112841311484.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 484113148211443 - 25 = 484113148211411 is a prime.
It is a super-2 number, since 2×4841131482114432 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (484113148211743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 242056574105721 + 242056574105722.
It is an arithmetic number, because the mean of its divisors is an integer number (242056574105722).
Almost surely, 2484113148211443 is an apocalyptic number.
484113148211443 is a deficient number, since it is larger than the sum of its proper divisors (1).
484113148211443 is an equidigital number, since it uses as much as digits as its factorization.
484113148211443 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1179648, while the sum is 49.
The spelling of 484113148211443 in words is "four hundred eighty-four trillion, one hundred thirteen billion, one hundred forty-eight million, two hundred eleven thousand, four hundred forty-three".
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