Base | Representation |
---|---|
bin | 101110001101110000… |
… | …101110001111111011 |
3 | 11202002022102120221002 |
4 | 232031300232033323 |
5 | 1303111442000214 |
6 | 34444013035215 |
7 | 3404463353363 |
oct | 561560561773 |
9 | 152068376832 |
10 | 49623000059 |
11 | 1a054987456 |
12 | 974a785b0b |
13 | 48aa922239 |
14 | 258a6359a3 |
15 | 14567261de |
hex | b8dc2e3fb |
49623000059 has 2 divisors, whose sum is σ = 49623000060. Its totient is φ = 49623000058.
The previous prime is 49623000013. The next prime is 49623000061. The reversal of 49623000059 is 95000032694.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49623000059 - 224 = 49606222843 is a prime.
Together with 49623000061, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 49622999986 and 49623000031.
It is a weakly prime.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24811500029 + 24811500030.
It is an arithmetic number, because the mean of its divisors is an integer number (24811500030).
Almost surely, 249623000059 is an apocalyptic number.
49623000059 is a deficient number, since it is larger than the sum of its proper divisors (1).
49623000059 is an equidigital number, since it uses as much as digits as its factorization.
49623000059 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 58320, while the sum is 38.
The spelling of 49623000059 in words is "forty-nine billion, six hundred twenty-three million, fifty-nine", and thus it is an aban number.
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