Base | Representation |
---|---|
bin | 101111100010011110… |
… | …100110100000101010 |
3 | 11212202100212202220221 |
4 | 233202132212200222 |
5 | 1314014321010010 |
6 | 35241024440254 |
7 | 3454632334306 |
oct | 574236464052 |
9 | 155670782827 |
10 | 51044313130 |
11 | 1a714202a58 |
12 | 9a8677908a |
13 | 4a762239a5 |
14 | 26832d4d06 |
15 | 14db3cadda |
hex | be27a682a |
51044313130 has 16 divisors (see below), whose sum is σ = 91947000960. Its totient is φ = 20402783632.
The previous prime is 51044313113. The next prime is 51044313161. The reversal of 51044313130 is 3131344015.
51044313130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 51044313095 and 51044313104.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1853350 + ... + 1880689.
It is an arithmetic number, because the mean of its divisors is an integer number (5746687560).
Almost surely, 251044313130 is an apocalyptic number.
51044313130 is a deficient number, since it is larger than the sum of its proper divisors (40902687830).
51044313130 is a wasteful number, since it uses less digits than its factorization.
51044313130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3735413.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 51044313130 its reverse (3131344015), we get a palindrome (54175657145).
The spelling of 51044313130 in words is "fifty-one billion, forty-four million, three hundred thirteen thousand, one hundred thirty".
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