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51044313130 = 2513673734039
BaseRepresentation
bin101111100010011110…
…100110100000101010
311212202100212202220221
4233202132212200222
51314014321010010
635241024440254
73454632334306
oct574236464052
9155670782827
1051044313130
111a714202a58
129a8677908a
134a762239a5
1426832d4d06
1514db3cadda
hexbe27a682a

51044313130 has 16 divisors (see below), whose sum is σ = 91947000960. Its totient is φ = 20402783632.

The previous prime is 51044313113. The next prime is 51044313161. The reversal of 51044313130 is 3131344015.

51044313130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 51044313095 and 51044313104.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1853350 + ... + 1880689.

It is an arithmetic number, because the mean of its divisors is an integer number (5746687560).

Almost surely, 251044313130 is an apocalyptic number.

51044313130 is a deficient number, since it is larger than the sum of its proper divisors (40902687830).

51044313130 is a wasteful number, since it uses less digits than its factorization.

51044313130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3735413.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 51044313130 its reverse (3131344015), we get a palindrome (54175657145).

The spelling of 51044313130 in words is "fifty-one billion, forty-four million, three hundred thirteen thousand, one hundred thirty".

Divisors: 1 2 5 10 1367 2734 6835 13670 3734039 7468078 18670195 37340390 5104431313 10208862626 25522156565 51044313130